For a matinee movie, a total of 260 tickets were sold. Ticket prices were $4.00/child, $6.50/adult. There was a total of $1227.50 in ticket revenue. How many tickets of each were sold? Enter two numbers.
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You need to make two equations so that you can solve for both unknowns.Let x = children's tickets and Let y = adults tickets. We know there are 260 tickets altogether.
`therefore x+y=260`
Now working with the cost, we know that children's tickets cost $4 therefore we have 4x and adults cost $6.50 so we have 6.5y with a total cost of $1227.50
`therefore 4x+6.5y=1227.50`
Now we can substitute to find the first unknown. You can solve for x or y first. We will solve for x, so taking the first equation we get
`x=260-y` which we substitute into the other equation:
`therefore 4(260-y)+6.5y=1227.50`
`therefore 1040-4y+6.5y=1227.50`
`therefore 2.5y=187.50`
`therefore y=75`
As y is the number of adults tickets, then that means there are 185 (260-75) tickets in teh children's category.
Ans:
185 children's tickets are sold and 75 adults' tickets.
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Let the number of child tickets sold be `x` .
So, the number of adult tickets sold =`(260-x)` .
Total price of the child ticket=`$ 4x`
Total price of the adult ticket=`$ 6.50(260-x)`
According to the given problem:
`4x+6.50(260-x)=1227.50`
`rArr 4x+1690-6.50x=1227.50`
`rArr 2.50x=462.50`
`rArr x=185`
So, number of child tickets sold=185
Hence, number of adult tickets sold=260-185=75
Therefore, 185 child tickets and 75 adult tickets were sold.
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