The triangle has vertexes A(2,3), B(1, -6), C(0,3)
AB = sqrt( 1 + 81) = sqrt 82
BC = sqrt(1 + 81) = sqrt 82
AC = 2
The area of a triangle is given by the Heron's formula as sqrt [s(s - a)(s - b)(s - c)] where a, b and c are the sides and s is the semi-perimeter.
s = sqrt 82 + 1
sqrt [s(s - a)(s - b)(s - c)]
=> sqrt [(sqrt 82 + 1)(1)(1)( sqrt 82 - 1)]
=> sqrt [ (82 - 1)]
=> 9
The area of the triangle is 9 square units.
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