If a material has an index of refraction of 2.25, what is the speed of light through it?
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Lix Lemjay
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To solve, apply the formula of index of refraction which is:
`n=c/v`
where,
n - index of refraction
c - velocity of light in a vacuum ( 3 x 10^8 m/s) and
v - velocity of light in a medium
So, plug-in n=2.25 and c=3 x 10^8 to the formula.
`2.25=(3xx10^8)/v`
Then, multiply both sides by v.
`2.25*v=(3xx10^8)/v * v`
`2.25v=3xx10^8`
And, divide both sides by 2.25.
`(2.25v)/2.25=(3xx10^8)/2.25`
`v=1.33xx10^8`
Hence, the velocity of light in the medium is `1.33xx10^8` m/s.
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