# A mass suspended on a spring will exhibit sinusoidal motion when it moves. http://postimage.org/image/76il2t78d/ Applications

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### 1 Answer

You should remember the equation of simple harmonic motion such that:

`y = A*sin (omega*t)`

Since the problem provides the end positions of the spring, you may evaluate peak-to-peak amplitude such that:

`2A =85 - 41 => A = (85 - 41)/2 => A = 44/2 => A = 22 cm`

The problem provides the period the complete movement is made, hence, the period of time is of 3 seconds.

You should remember the equation that relates the frequency f, the angular frequency omega and the period T such that:

`T = 1/f and f = (omega)/(2pi) => T = 2pi/omega => omega = 2pi/T`

`omega = 2pi/3`

Hence, substituting `2pi/3` for omega in equation of simple harmonic motion yields:

`y = 22*sin ((2pi/3)*t)`

**Hence, evaluating the equation that models the simple harmonic motion yields `y = 22*sin ((2pi/3)*t)` .**

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