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Let the mass of a Bobcat be B.
Let the mass of an Arctic wolf be A.
Given that the mass for both is 48 kg.
==> A + B = 48 ................(1)
But we are also given that the mass of B is 1/5 of the mass of A.
==> B = 1/5 * A................(2)
Now we will solve the system by substituting (2) into (1).
==> A + (1/5 * A) = 48
==> (6/5)*A = 48
We will multiply by 5/6
==> A = 48 * 5/6 = 40
==> B = 1/5 * 40 = 8
Then, the mass of the Bobcat is 8 kg.
The mass of the Arctic Wolf is 40 kg.
The answer to this question is that the Arctic Wolf is 40 kg. and the bobcat is 8 kg. You can set up the equation as 1/5 X + X =48kg. Next, multiply 1/5 X by 5 to make it a whole number, or X. Multiply X by 5 also and then add X +5X together which becomes 6X. Then, rewrite the equation as 6X=48kg. Divide both sides by 6 and you arrive at X = 8 kg. Therefore, if the bobcat is X and the Arctic Wolf is 5X, then the bobcat is 8kg and the Arctic wolf is 5(8kg) or 40kg.
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