A man travels from A to B at 4 km/h and from B to A at 6 km/h. The total journey takes 45 minutes. Find the distance traveled.
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hala718
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Let the distance from A to B is D
Then, the distance from B to A is also D.
Let us use the distance formula to find D.
We know that:
D = Speed * Time
Given that the speed from A to B is S1 = 4
==> D = 4 * T1
Also given that the speed from B to A is S2 = 6
==> D = 6 * T2
Then D = D
==> 4T1 = 6T2 .............(1)
But we know that the total time is 45 min
==> 45 min = 3/4 hour.
==> T1 + T2 = 3/4
We will substitute into (1).
==> 4T1 = 6 ( 3/4 - T1)
==> 4T1 = 9/2 - 6T1
==> 10T1 = 9/2
==> T1 = 9/20 = 0.45 hour
==> T2 = 3/4 - 9/20 = 6/20 = 0.3 hour
Then D = 4*T1 = 4* 0.45 = 1.8 km
Then, the distance is 1.8 km.
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