To make one bowl of punch using lemonade and soda pop, we require the two in the ratio 2:3.

For a quantity of punch equal to 5x, the lemonade required is 2x and the soda pop required is 3x.

Here 25 gallons of soda pop are made, so we require 2*25 / 5 = 10 gallons of lemonade.

**The required volume of lemonade is 10 gallons.**

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Given that the ration of the lemon to the soda pop into a lemonade mix is 2:3

If there are 25 gallons of punch, how much lemonade is needed?

Let the amount of lemonade = x

The amount of soda pop = y

Then we know that:

x /y = 2/3

==> 3x = 2y .............(1)

But we are given that the punch is 25 gallon.

==> x + y = 25 ............(2)

Let us substitute with x = 25-y into (1).

==> 3x = 2y

==> 3(25-y) = 2y

==> 75 - 3y = 2y

==> 5y = 75

==> y= 75/5 = 15

==> x= 25-15 - 10

**Then we need 10 gallons of lemonade and 15 gallons of soda pops.**

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