To make one bowl of punch using lemonade and soda pop, we require the two in the ratio 2:3.
For a quantity of punch equal to 5x, the lemonade required is 2x and the soda pop required is 3x.
Here 25 gallons of soda pop are made, so we require 2*25 / 5 = 10 gallons of lemonade.
The required volume of lemonade is 10 gallons.
Given that the ration of the lemon to the soda pop into a lemonade mix is 2:3
If there are 25 gallons of punch, how much lemonade is needed?
Let the amount of lemonade = x
The amount of soda pop = y
Then we know that:
x /y = 2/3
==> 3x = 2y .............(1)
But we are given that the punch is 25 gallon.
==> x + y = 25 ............(2)
Let us substitute with x = 25-y into (1).
==> 3x = 2y
==> 3(25-y) = 2y
==> 75 - 3y = 2y
==> 5y = 75
==> y= 75/5 = 15
==> x= 25-15 - 10
Then we need 10 gallons of lemonade and 15 gallons of soda pops.