Magnesium sulfate is called Epsom salt. If one needed 4.23 moles of this compound, what mass would you need.
2 Answers
jerichorayel | College Teacher | (Level 2) Senior Educator
To solve for this problem, we need to employ the molar mass - moles ratio. Remember that:
`Number of mol es of any compound = (Given mass)/(molar mass)`
Since we are after to the given mass, we can have it as:
`Given mass = Molar mass * Number of mol es`
`Given mass = (4.23 mol es Magn esium s u l f a te)*(120.366 (grams)/(mol e))`
Given mass = 509.15 Grams Magnesium sulfate
Note: The molar mass of Magnesium sulfate is 120.366
maxim777 | Student, Undergraduate | (Level 2) eNoter
First let's molar mass of MgSO4:
M(MgSO4) = 24 + 32 + (16*4) = 120 g/mol
Mass of the substance is calculated by the formula:
m = M(MgSO4)*n(MgSO4)
m (MgSO4) = 120 g/mol * 4.23 g = 507.6 g
Answer: m (MgSO4) = 507.6 g