log x + log 2x = 3 log 2    find x values

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log x + log 2x = 3 log 2

We know that:

log a + log b = log a*b

==> log x + log 2x = log 2x^2

==> log 2x^2 = 3 log 2

Also, we know that:

a log b = log b^a

==> 3 log 2...

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log x + log 2x = 3 log 2

We know that:

log a + log b = log a*b

==> log x + log 2x = log 2x^2

==> log 2x^2 = 3 log 2

Also, we know that:

a log b = log b^a

==> 3 log 2 = log 2^3 = log 8

==> log 2x^2 = log 8

==> 2x^2 = 8

Now divide by 2:

==> x^2 = 4

==> x= 2

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