`log(x) = -2` Solve for `x`.

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Chapter 3, 3.4 - Problem 12 - Precalculus (3rd Edition, Ron Larson).
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loves2learn | (Level 3) Salutatorian

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Assume `log_10 `

`log_(10)x=-2 `

`10^-2=x `

`x=0.01 `

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