If log(x) 1/8 = -3/2, what is x >
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calendarEducator since 2008
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Given that log(x) 1/8 = -3/2
We need to find x value.
First we will rewrite the fraction (1/8)
==> We know that 1/8 = (1/2)^3 = 1/2^3 = 2^-3
We will substitute.
==> log(x) 2^-3 = -3/2
Now we know that log a^b = b*log a
==> -3*logx 2 = -3/2
We will divide by -3.
==> logx 2 = 1/2
Now we will rewrite into the exponent form.
=> x^1/2 = 2
Now we will square both sides.
==> x = 4
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calendarEducator since 2010
write12,544 answers
starTop subjects are Math, Science, and Business
We have to find x from log(x) 1/8 = -3/2
log(x) 1/8 = -3/2
=> log (x) 8^-1 = -3/2
=> log (x) 4^(-3/2) = -3/2
take the antilog of both the sides
=> 4^(-3/2) = x^(-3/2)
as the exponent is the same, we can equate the base
=> x = 4
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