`log_pi (pi)` Use the properties of logarithms to simplify the expression.

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Chapter 3, 3.2 - Problem 27 - Precalculus (3rd Edition, Ron Larson).
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loves2learn | (Level 3) Salutatorian

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The log base of some value to the some value always equals 1. (`log_a(a)=1 ` )

Therefore, this simplifies down to

`1 `

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