Given `log_3 8~~1.8928` , evaluate `log_3 72` :

`log_3 72=log_3 (8*9)` Use `log(AB)=logA+logB`

`=log_3 8 + log_3 9` but `log_3 9=2` since `3^2=9`

`=log_3 8 +2`

`~~3.8928`

Calculator value is 3.892789261

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