`log_b (sqrt(2))` Approximate the logarithm using the properties of logarithms, given `log_b (2) ~~ 0.3562, log_b (3) ~~ 0.5646, and log_b (5) ~~ 0.8271`.

Textbook Question

Chapter 3, 3.3 - Problem 62 - Precalculus (3rd Edition, Ron Larson).
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loves2learn | (Level 3) Salutatorian

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`log_bsqrt2=log_b2^(1/2) `

`log_bsqrt2=(1/2)log_b2 `

`log_bsqrt2=(1/2)0.3562 `

`log_bsqrt2=0.1781 `

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