`log_b (2/3)` Approximate the logarithm using the properties of logarithms, given `log_b (2) ~~ 0.3562, log_b (3) ~~ 0.5646, and log_b (5) ~~ 0.8271`.

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Chapter 3, 3.3 - Problem 60 - Precalculus (3rd Edition, Ron Larson).
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loves2learn | (Level 3) Salutatorian

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`log_b(2/3)=log_b2-log_b3 `

`log_b(2/3)=0.3562-0.5646 `

`log_b(2/3)=-0.2084 `

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