`log_b (10)` Approximate the logarithm using the properties of logarithms, given `log_b (2) ~~ 0.3562, log_b (3) ~~ 0.5646, and log_b (5) ~~ 0.8271`.

Textbook Question

Chapter 3, 3.3 - Problem 59 - Precalculus (3rd Edition, Ron Larson).
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loves2learn | (Level 3) Salutatorian

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`log_b10=log_b(2*5) `

`log_b2+log_b5=log_b10 `

`0.3562+0.8271=log_b10 `

`log_b10=1.1833 `

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