`log(5x + 3) = log(12)` Use the One-to-One Property to solve the equation for `x`.

Textbook Question

Chapter 3, 3.2 - Problem 32 - Precalculus (3rd Edition, Ron Larson).
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loves2learn | (Level 3) Salutatorian

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Since you have logs with the same bases on both sides, they cancel leaving you with

`5x+3=12`

Solve for x

`x=1.8`

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