`log_5 (x + 1) = log_5 (6)` Use the One-to-One Property to solve the equation for `x`.

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Textbook Question

Chapter 3, 3.2 - Problem 29 - Precalculus (3rd Edition, Ron Larson).
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loves2learn | (Level 3) Salutatorian

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Since you have logs with the same bases on both sides, they cancel leaving you with

`x+1=6 `

Solve for x

`x=5 `

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