`log_5 (8) - log_5 (t)` Condense the expression to the logarithm of a single quantity.

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Chapter 3, 3.3 - Problem 68 - Precalculus (3rd Edition, Ron Larson).
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loves2learn | (Level 3) Salutatorian

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Condense using division,


`log_5(8)-log_5t `

Therefore, it becomes

`log_5(8/t) `

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