`log_5 (1/250)` Use the properties of logarithms to rewrite and simplify the logarithmic expression.

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Chapter 3, 3.3 - Problem 17 - Precalculus (3rd Edition, Ron Larson).
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loves2learn | (Level 3) Salutatorian

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`log_5 (1/250) = log_5(1/125) + log_5(1/2)`
`log_5 (1/250) = log_5 (5^-3) + log_5 (2^-1) `
`log_5 (1/250) = -3 + -1*log_5(2) `
`log_5 (1/250) = -3 - log_5(2) `

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