If log_4 x^2 = 32 what is x.
I will solve the logarithmic equation creating matching bases to the left and to he right of equal.
To the left side tells us what is the base of logarithm, so I will create the logarithm in base 4 to the right.
First, I will consider 32 multiplied by 1. Notice that it does not change a thing this multiplication. Take a look!
log_4 x^2 = 32*1
Now, I will put log_4 (4) in the place of 1:
log_4 x^2 = 32*log_4 (4)
All I need to do is to make use of logarithmic rule of powers and to transform 32 in the exponent of number 4:
log_4 x^2 = log_4 4^32
Now the matching bases make the things much more easy because you just need to set equal the arguments of logarithms. Take a look:
x^2 = 4^32
We must solve for x and not for x^2, so you should consider taking square roots to the left and to the right, same time:
sqrt(x^2) = sqrt(4^32)
|x| = 4^16
Take out the modulus and you will get the final results. Watch out because there are two results, one positive, one negative!
x = +-4^16
The final answer is x = +-4^16.
The equation `log_4 x^2 = 32` has to be solved for x.
`log_4 x^2 = 32`
=> `x^2 = 4^32`
=> `x^2 = (2^2)^32`
=> `x^2 = (2^32)^2`
=> `x = +-2^32`
The solution of the equation is `x = +-2^32`