# `log(3x + 4) = log(x - 10)` Solve the logarithmic equation algebraically. Approximate the result to three decimal places.

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### 1 Answer

Since you have logs on both sides, just set the inner parts equal to each other

`3x+4=x-10 `

From here, it is simple algebra, just simplify,

`x=-7 `

But this is not considered a real solution since you cannot take the log on a negative number.