`log_2 (x) + log_2 (x + 2) = log_2 (x + 6)` Solve the logarithmic equation algebraically. Approximate the result to three decimal places.
Since they are both `log_2 ` , rewrite it using properties of logs
Exponentiate both sides by 2 and solve for x
`x=-3 ` and `x=2 `
Since you cannot take the log of a negative number, `x=-3 ` is not viable.
Therefore, your answer is `x=2 `