`log_2 (x - 3) = log_2 (9)` Use the One-to-One Property to solve the equation for `x`.

Textbook Question

Chapter 3, 3.2 - Problem 30 - Precalculus (3rd Edition, Ron Larson).
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loves2learn | (Level 3) Salutatorian

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Since you have logs with the same bases on both sides, they cancel leaving you with

`x-3=9 `

Solve for x

`x=12 `

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