Hello!

"Accelerates backward" probably means "decelerates". In other words, the acceleration is `- 0.08 m / s^2` while the initial velocity is `1.0 m / s .` This way the velocity at a time t seconds is `v = v( t ) = 1.0 - 0.08 t .`

The average...

## Unlock

This Answer NowStart your **48-hour free trial** to unlock this answer and thousands more. Enjoy eNotes ad-free and cancel anytime.

Already a member? Log in here.

Hello!

"Accelerates backward" probably means "decelerates". In other words, the acceleration is `- 0.08 m / s^2` while the initial velocity is `1.0 m / s .` This way the velocity at a time t seconds is `v = v( t ) = 1.0 - 0.08 t .`

The average value of this velocity from `t = 0` seconds to `t = 4` seconds is

`1 / 4 int_0^4 (1.0 - 0.08 t) dt = 1 / 4 (t - 0.04 t^2 )_(t=0)^4 = `

`=1 - 0.01 * 16 = 1 - 0.16 = 0.84 (m / s) . `

So, although the velocity of the remote controlled vehicle decreases, it remains positive and its average is also positive, namely `0.84 m /s .`