`ln(z) (z - 1)^2, z > 1` Use the properties of logarithms to expand the expression as a sum, difference, and or constant multiple of logarithms. (Assume all variables are positive.)

1 Answer

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loves2learn | (Level 3) Salutatorian

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Since all of the terms are multiplied together, one can expand by adding them together.

Given,

 `ln((z)(z-1)^2)`

Then,

` ln((z)(z-1)^2)=lnz+2ln(z-1) `