`ln(x - 7) = ln(7)` Use the One-to-One Property to solve the equation for `x`.

Textbook Question

Chapter 3, 3.2 - Problem 74 - Precalculus (3rd Edition, Ron Larson).
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loves2learn | (Level 3) Salutatorian

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Since there are ln's on both sides, set the terms equal to each other.

`x-7=7`

Solve for x

`x=14`

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