# `ln(x^2 - x) = ln(6)` Use the One-to-One Property to solve the equation for `x`.

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Student Comments

loves2learn | Student

Since there are ln's on both side, they cancel and set the two parts equal to each other.

`x^2-x=6`

Solve for x

`x^2-x-6=0`

Factor

`(x-3)(x+2)=0`

`x=3` and `x=-2`