`ln(x^2 - x) = ln(6)` Use the One-to-One Property to solve the equation for `x`.

Textbook Question

Chapter 3, 3.2 - Problem 76 - Precalculus (3rd Edition, Ron Larson).
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loves2learn | (Level 3) Salutatorian

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Since there are ln's on both side, they cancel and set the two parts equal to each other.

`x^2-x=6`

Solve for x

`x^2-x-6=0`

Factor

`(x-3)(x+2)=0`

`x=3` and `x=-2`

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