`ln((x^2 - 1)/(x^3)), x > 1` Use the properties of logarithms to expand the expression as a sum, difference, and or constant multiple of logarithms. (Assume all variables are positive.)

loves2learn | Student

Expand using subtraction because the terms are being divided in the ln.


`ln((x^2-1)/(x^3)) `

Then, after expanded and bringing down the exponents where necesarry

`ln((x^2-1)/(x^3))= ln(x^2-1)-3lnx, x>1`