`ln(sqrt(z))` Use the properties of logarithms to expand the expression as a sum, difference, and or constant multiple of logarithms. (Assume all variables are positive.)

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Textbook Question

Chapter 3, 3.3 - Problem 43 - Precalculus (3rd Edition, Ron Larson).
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loves2learn | (Level 3) Salutatorian

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Bring down the exponent,

`lnsqrtz=lnz^(1/2) `

Therefore,

`lnsqrtz=(1/2)lnz `

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