ln e^(x+2) = 5 + ln e^2

We know that:

ln e^a = aln e = a*1 = a

==> ln e^(x+2) = 5 + ln e^2

==> (x+2) = 5 + 2

==> x+2 = 7

==> x= 7-2

==> x= 5

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