ln e^(x+2) = 5 + ln e^2
We know that:
ln e^a = aln e = a*1 = a
==> ln e^(x+2) = 5 + ln e^2
==> (x+2) = 5 + 2
==> x+2 = 7
==> x= 7-2
==> x= 5
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