`ln(6/(e^2))` Use the properties of logarithms to rewrite and simplify the logarithmic expression.

Textbook Question

Chapter 3, 3.3 - Problem 20 - Precalculus (3rd Edition, Ron Larson).
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loves2learn | (Level 3) Salutatorian

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`ln(6/e^2) `

When you divide inside the ln, you subtract when you expand

`ln(6) - ln(e^2) `

Bring down the exponent and remember than `lne=1 `

`ln(6) - 2 `

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