# linear analytical inequalitiesx+y=1, 3x-y=-5 2x-y=5, 3x+y=5 solve by graphing

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### 3 Answers

You need to solve the simultaneous equations x+y=1 and 3x-y=-5, hence I suggest to eliminate the variable y such that:

x+y+3x-y=-5+1 =>4x= -4 => x = -1

You need to substitute -1 for x in equation x+y=1 such that:

-1+y=1 => y = 2

**Hence, the solution to simultaneous equations is x=-1; y=2.**

You need to solve the simultaneous equations 2x-y=5 and 3x+y=5, hence I suggest to eliminate the variable y such that:

2x-y+3x+y=5+5 => 5x = 10 => x = 2

You need to substitute 2 for x in equation 3x+y=5 such that:

6+y=5 => y = 5-6=> y=-1

**Hence, the solution to simultaneous equations 2x-y=5 and 3x+y=5 is x=2; y=-1.**

You would have to post the equations this as a question for a graphical solution. The algebraic solution for the two is

- x+y=1, 3x-y=-5

x + y = 1

=> x = 1 - y

substitute in 3x - y = -5

=> 3 - 3y - y = -5

=> y = 2

x = -1

- 2x-y=5, 3x+y=5

2x - y = 5

=> y = 2x - 5

substitute in 3x + y = 5

=> 3x + 2x - 5 = 5

=> x = 2

y = -1