linear analytical inequalities x+y=1, 3x-y=-5 2x-y=5, 3x+y=5 solve by graphing

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You need to solve the simultaneous equations x+y=1 and 3x-y=-5, hence I suggest to eliminate the variable y such that:

x+y+3x-y=-5+1 =>4x= -4 => x = -1

You need to substitute -1 for x in equation x+y=1 such that:

-1+y=1 => y = 2

Hence, the solution to simultaneous equations is x=-1; y=2.

You need to solve the simultaneous equations 2x-y=5 and 3x+y=5, hence I suggest to eliminate the variable y such that:

2x-y+3x+y=5+5 => 5x = 10 => x = 2

You need to substitute 2 for x in equation 3x+y=5 such that:

6+y=5 => y = 5-6=> y=-1

Hence, the solution to simultaneous equations 2x-y=5 and 3x+y=5 is x=2; y=-1.

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You would have to post the equations this as a question for a graphical solution. The algebraic solution for the two is

  • x+y=1, 3x-y=-5

x + y = 1

=> x = 1 - y

substitute in 3x - y = -5

=> 3 - 3y - y = -5

=> y = 2

x = -1

  • 2x-y=5, 3x+y=5

2x - y = 5

=> y = 2x - 5

substitute in 3x + y = 5

=> 3x + 2x - 5 = 5

=> x = 2

y = -1

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We can't graph here, but can tell you how to solve this by graphing. First, you need to graph each function. Solve each for y. They are equations here. You will note the slope next to the x and the y intercept as the second number. Graph each, and see where they intersect. That point is your solution.
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