# If line segment PQ is congruent to line segment RS, and `PQ= x ^2-5` , and `RS = 2x+3` , then find PQI solved it out and set PQ equal to RS and factored it and got x= -2 and 4. But, when you plug...

If line segment PQ is congruent to line segment RS, and `PQ= x ^2-5` , and `RS = 2x+3` , then find PQ

I solved it out and set PQ equal to RS and factored it and got x= -2 and 4. But, when you plug either one back into the equation for PQ, it turns out negative and you can't have a negative measure for a line segment...

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Your solution is correct. Let's try to do it again to clarify.

Since PQ and RS are congruent, to solve for x, set PQ=RS.

`PQ=RS`

`x^2-5=2x+3`

`x^2-2x-8=0`

Factor left side.

`(x-4)(x+2)=0`

Set each factor to zero and solve for x.

`x-4=0` and `x+2=0`

`x=4` `x=-2`

Substitute the values of x to PQ and RS.

`x=4` , `PQ=4^2-5=11` and `RS=2(4)+3=11`

`x=-2` , `PQ=(-2)^2-5=-1` and `RS=2(-2)+3=-1`

Since PQ and RS represents the length of the line segment, then take only the positive values.

**Hence, PQ=RS=11 units.**