The line r= (-8,-6,-1) + s(2,2,1), sER, intersects the xz- and yz-coordinate planes at the points A and B, respectively. Determine the length of...line segment AB.

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justaguide | College Teacher | (Level 2) Distinguished Educator

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We have to find the distance between the points A and B which are the points of intersection of the line of the line r= (-8,-6,-1) + s(2,2,1), and the xz and yz-coordinate planes respectively.

The equation of the xz plane is y = 0 and that of the yz plane is x = 0.

r= (-8,-6,-1) + s(2,2,1) can be written as

(x + 8)/2 = (y + 6)/2 = (z + 1)/1 = t

A point on the line can be expressed as (2t - 8 , 2t - 6, t - 1)

The point A is where the line intersects y = 0

=> 2t - 6 = 0

=> t = 3

The required point A is (-2, 0, 2)

Similarly for point B, the equation of the plane is x = 0.

=> 2t - 8 = 0

=> t = 4

The point B is (0 , 2, 3)

The distance between the points A and B is sqrt [(x1 - x2)^2+ (y1 - y2)^2 + (z1 - z2)^2]

=> D = sqrt [ ( 0 + 2)^2 + (2 - 0)^2 +(3 - 2)^2]

=> D = sqrt (4 + 4 + 1)

=> D = sqrt 9

=> D = 3

The length of the line segment AB = 3 units.

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