Line L passes through the points (4 , -5) and (3 , 7). Find the slope of any line perpendicular to line L.
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calendarEducator since 2008
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Given the points ( 4, -5) and the point ( 3, 7) passes through line L.
We need to find the slope of any perpendicular line to L.
First we will determine the slope of L.
We know that:
m = (y2-y1)/(x2-x1) = (7+5) / (3-4) = 12/-1 = -12
Now we know that the product of the slopes of two perpendicular line is -1.
==> Let m1 be the slope of any perpendicular line.
==> m * m1 = -1
==> -12 * m1 = -1
==> m1= 1/12
The slope of any perpendicular line to L is 1/12.
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calendarEducator since 2010
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The slope of the line L passing through the points ( 4 , -5) and (3 , 7) is given by :
slope = ( -5 - 7) / (4 - 3)
=> -12 / 1
The slope of a line perpendicular to this would be m such that m*(-12) = -1
=> m = 1/12
The required slope of the line is 1/12
The slope of the given line is:
m = [7-(-5)]/(3-4)
m = 12/-1 = -12
The slope of the perpendicular line is m1 and we know that the product of the slopes of 2 perpendicular lines is -1.
m*m1 = -1
-12*m1 = -1
m1 = 1/12
The slope of the perpendicular line is: m1 = 1/12.
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