A line has equation y = kx + 6 and a curve has equation y = x^2 + 3x + 2k, where k is a constant. (i) For the case where k = 2, the line and the curve intersect at points A and B. Find the distance AB and the coordinates of the mid-point of AB.

Expert Answers

An illustration of the letter 'A' in a speech bubbles

`y = kx+6`

`y = x^2+3x+2k`

when k= 2

`y = 2x+6`

`y= x^2+3x+4`

At intersecting points;

`2x+6 = x^2+3x+4`

`0=x^2+x-2`

`0=x^2+2x-x-2`

`0=x(x+2)-1(x+2)`

`0=(x+2)(x-1)`

`x=-2` and `x=1`

When x= -2 then y = 2

When x = 1 then y = 8

`A=(-2,2)`

`B=(1,8)`

Distance AB `= sqrt((-2-1)^2+(2-8)^2) = sqrt(3^2+6^2) = 3 sqrt(5)`

Mid point of AB `= (1/2)(-2+1),(1/2)(2+8) = (-1/2 , 5)`

So the distance AB is `3sqrt(5)` units and mid point of AB is `(-1/2,5)`

Approved by eNotes Editorial Team

We’ll help your grades soar

Start your 48-hour free trial and unlock all the summaries, Q&A, and analyses you need to get better grades now.

  • 30,000+ book summaries
  • 20% study tools discount
  • Ad-free content
  • PDF downloads
  • 300,000+ answers
  • 5-star customer support
Start your 48-Hour Free Trial