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`lim x->oo (x^2 + 2)/(x-1)`
`or, lim x->oo (2x)/1`
`or, lim x-> (2x) = oo`
Plug in `oo ` everywhere you have x
Since you have , you can use L^Hopital's Rule and differentiate the numerator and denominator independently.
the `lim_(x->oo)(x^2+2)/(x-1)=oo `
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