`lim_(x->oo) ln(x)/sqrt(x)` Find the limit. Use l’Hospital’s Rule where appropriate. If there is a more elementary method, consider using it. If l’Hospital’s Rule doesn’t apply, explain why.
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Apply L'Hospital rule , Test L'Hospital condition:`oo/oo`
plug in the value,
Use LH's rule
square root of infinity is still infinity. 2 divided by a really big number (like infinity) is just 0.
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