Given,

`lim_(x->-oo)` cschx

`= lim_(x->-oo) (2/(e^x -e^(-x)))`

as x -> to negative infinity ` e^x -> 0 ` and `e^-x` tends to negative infinity

so,

`lim_(x->-oo) (2/(e^x -e^(-x))) = lim_(x->-oo) (2/(0 -(-oo))) = 0`

## See eNotes Ad-Free

Start your **48-hour free trial** to get access to more than 30,000 additional guides and more than 350,000 Homework Help questions answered by our experts.

Already a member? Log in here.