`lim_(x -> -oo) (5x^2)/(x + 3)` Find the limit.

Expert Answers
hkj1385 eNotes educator| Certified Educator

Since this is a `(-oo)/(-oo)`  form

Thus, applying L'Hospital's rule we get

`lim_(x->-oo)(5x^2)/(x+3) = lim_(x->-oo) (10x) = -oo`

``

``

` `

scisser | Student

Plug in` -oo` everywhere you have x

`lim_(x->-oo)(5(-oo)^2)/(-oo+3)=(-oo)/-oo `

Since you have , you can use L^Hopital's Rule and differentiate the numerator and denominator independently.

`lim_(x->-oo)10x=-oo `

Therefore,

the `lim_(x->-oo)(5x^2)/(x+3)=-oo `

Access hundreds of thousands of answers with a free trial.

Start Free Trial
Ask a Question