`lim_(x->0) (sin(3x) sin(5x))/x^2` Find the limit.

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kspcr111 | In Training Educator

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`lim_(x->0) (sin(3x) sin(5x))/x^2`

As x->0 then `sin(nx) = nx`

so,

`=lim_(x->0) (sin(3x) sin(5x))/x^2`

`=lim_(x->0) ((3x) (5x))/x^2`

=lim_(x->0) ((3*5*x^2))/x^2

= 15