`lim_(x->0) (sin(3x) sin(5x))/x^2` Find the limit.

Textbook Question

Chapter 3, 3.3 - Problem 44 - Calculus: Early Transcendentals (7th Edition, James Stewart).
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kspcr111 | In Training Educator

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`lim_(x->0) (sin(3x) sin(5x))/x^2`

As x->0 then `sin(nx) = nx`

so,

`=lim_(x->0) (sin(3x) sin(5x))/x^2`

`=lim_(x->0) ((3x) (5x))/x^2`

=lim_(x->0) ((3*5*x^2))/x^2

= 15

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