Since the order of how the books are chosen is irrelevant, this is a combination problem.

The number of different selections is C(18,3) which is

`{18!}/{3!(18-3)!}`

`={18!}/{3!15!}` simplify numerator

`={18 times 17 times 16 times 15!}/{3!15!}` cancel common factors

`=3 times 17 times 16`

`=816`

**There are 816 different possible selections of the book titles.**

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