**If A is an element of B and B is a subset of C, then A is a subset of C.**

B is a subset of C implies that every element of B is contained in C. Since A is an element of B, it must be an element of C.

** If you meant to start with 3 sets A,B,C and `a in A,a in B,B sub C` then the answer is false. Here we just know that a(an element) lies in C, as opposed to the whole set A being contained in C.

Let A be the even numbers, B be the multiples of 3, and C be the multiples of 6. a=6 is clearly in A,B, and C, but A is not a subset of either B or C.

Let A be the set of rational numbers, B the set of natural numbers and C the set of integers. Then a=3 is clearly in B and C, but A is not a subset of B or C.

## We’ll help your grades soar

Start your 48-hour free trial and unlock all the summaries, Q&A, and analyses you need to get better grades now.

- 30,000+ book summaries
- 20% study tools discount
- Ad-free content
- PDF downloads
- 300,000+ answers
- 5-star customer support

Already a member? Log in here.

Are you a teacher? Sign up now