# The lengths of 2 sides of a kite are 7.6cm & 4.3cm.Length of the shorter diogonal of the kite is 5.2cm.Use a ruler & compass to construct.Please explain to me and if possible, please give...

The lengths of 2 sides of a kite are 7.6cm & 4.3cm.Length of the shorter diogonal of the kite is 5.2cm.Use a ruler & compass to construct.

Please explain to me and if possible, please give me some links to understand how to construct kites. It is also asked to show all the construction lines in this question. Please I really need help on this

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A kite can be considered to be 2 isosceles triangles sharing the side which has a different length.

To construct the kite, follow these steps:

- First draw a straight line segment equal to the length of the shorter diagonal. Let's name this AB. So AB has a length of 5.2 cm.
- Now using your compass set its width to the length of the smaller side, which is 4.3 cm. Set the compass on A and draw an arc. Draw another arc with the compass set on B and intersect the earlier arc you had drawn. Indicate the point of intersection of the two arcs as C.
- Repeat what you did in step 2, but this time set the width of the compass equal to the length of the longer side, which in this case would be 7.6 cm. Also, this time indicate the point of intersection of the two arcs as D.
- Once you have marked the points A, B, C and D, join AC, CB, BD and DA using your ruler.

The kite you wanted to construct is ACBD.

Hope you had fun doing it.

Also, check out the attached link.

A kite is quadrilateral (convex) in which a pair of adjascent sides are equal and the respective opposite pair of adjascent sides are equal. The digagonals intersect at right angles. The shorter diagonal is bisected.

A quadrilateral ABCD is a kite AB = AD and CD = CB. The diagonals AC and DB intersect at right angles.

In the given case,

AB =AD= 4.3cm

CD = CB = 7.6 cm

The diagonal DB = 5.2 cm

Construction:

Draw DB 5.2cm.

Take 4.3 cm as radius in compass and with D as centre draw an arc to cut the arc with same radius drawn with centre B. Let the intersection of arcs be A.

Now take 7.6cm radius and draw arcs on the other side of DB with centre D and B to intersect at C.

Now by construction DB = 5.2, AD = AC =4.3cm , CD = CB = 7.6cm. So ABCD is the required kite.