length of rectangle is three feet more than the width. Its perimeter is 102. Find the length and width
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Given: Rectangle whose length is 3 feet more than its width and the perimeter of the rectangle is 102 feet.
Let P represent the variable for the perimeter. P=102 feet.
Let x represent the variable for the width.
From the given we know that the length of the rectangle is 3 feet more than the width. This means that the length is equal to x+3.
The formula for the perimeter of a rectangle is
P=2(length)+2(width)
P=2(x+3)+2x
102=2x+6+2x
102=4x+6
96=4x
24=x
Since the width is the variable for x. We know that the width of the rectangle is 24 feet.
The length of the rectangle is the expression x+3.
Since the length=x+3, when we substitute 24 in for x, we know that the
length=24+3=27 feet.
Final answer:
The length of the rectangle is 27 feet and the width is 24 feet.
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