Describe the steps, including calculations, you would need to follow to prepare 150ml of a 0.25 mol/L solution of lead(ii)nitrate. Be sure to provide enough detail in your process that a student could follow the steps to produce the solution.
You are only allowed to ask one question at a time so I edited accordingly. We are looking to make 150 mL of a 0.25 M solution of lead nitrate. Basically, we need to figure out how many grams of lead nitrate are need to add to 150 mL of water to make a 0.25 M solution (M is molarity meaning moles per liter). Since we know the molarity of the final solution and the volume...
(The entire section contains 207 words.)
check Approved by eNotes Editorial