A lady buys two articles whose marked prices are the same. On one of them she pays a sales tax of 8% and on the other 6% while purchasing the articles. If she pays Rupees 8 more for the first...

A lady buys two articles whose marked prices are the same. On one of them she pays a sales tax of 8% and on the other 6% while purchasing the articles. If she pays Rupees 8 more for the first article, find the price which the lady pay for the two articles together.

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tjbrewer | Elementary School Teacher | (Level 2) Associate Educator

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The question tells us that the two items are the same price, so we designate that as variable `x` We are told that one item has an 8% sales tax making its price `x+.08x=1.08x` And the other item has a sales tax of 6% making its price `x+.06x=1.06x` We are then told the difference in price is 8 rupees.  Difference means subtraction, so we apply subtraction to our terms and we find `1.08x-1.06x=8` We combine like terms `.02x=8` Solve for x and find `x=8-:.02=400`

We know that each item has a base price of 400 rupees.  We then plug 400 into our original price findings and find the sum to determine the combined price `1.08(400)+1.06(400)=432+424=856`

The woman pays a total of 856 rupees for the two items. 

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