A lady buys two articles whose marked prices are the same. On one of them she pays a sales tax of 8% and on the other 6% while purchasing the articles. If she pays Rupees 8 more for the first article, find the price which the lady pay for the two articles together.
The question tells us that the two items are the same price, so we designate that as variable `x` We are told that one item has an 8% sales tax making its price `x+.08x=1.08x` And the other item has a sales tax of 6% making its price `x+.06x=1.06x` We are then told the difference in price is 8 rupees. Difference means subtraction, so we apply subtraction to our terms and we find `1.08x-1.06x=8` We combine like terms `.02x=8` Solve for x and find `x=8-:.02=400`
We know that each item has a base price of 400 rupees. We then plug 400 into our original price findings and find the sum to determine the combined price `1.08(400)+1.06(400)=432+424=856`
The woman pays a total of 856 rupees for the two items.