# Kyle has a lock combination with three digits. Every number in the combination must be a 0-4. What is the probability that his combination is 000?

Probability of getting 0 as a digit, p = 1/5 (only one chance in 5, other options could be 1,2,3,4)

Probability of not getting 0 as a digit, q = 1-1/5 = 4/5

The probability of getting 000 as lock combination is same as getting the 0 three times in a row. We can use the following equation to solve the question:

`P(x=k) = (n k) p^k q^(n-k)`

Here, k =3,

Therefore the probability, P = (3 3) `(1/5)^3 (4/5)^(3-3) = (1/5)^3 = 1/125`

Hope this helps.

Kyle has a lock combination of **three **digits. Each of those numbers can be either 0, 1, 2, 3, or 4. Those are **five **numbers.

To get the total amount of combinations, you can basically do this:

`5^3`

Five cubed, or five to the third power. The five means that there are five numbers, and the three means that there is three slots for those five numbers. So, basically,

`5^3=5*5*5`

5 cubed means five multiplied by itself **three** times. So, if we do that,

`5*5=25;`

`25*5=125`

Thus, 125 is the **total amount of combination possibilities for Kyle's lock.**

Now, what is the probability of Kyle's lock being 000? Well, 000 is **only** one combination. So, that's **one** combination out of the **125 TOTAL **possibilities for his combination. Given that, we can create the fraction

`1/125`

I hope I helped!

*In case you need to know the percentage, you can just do 1/125 and get a decimal 0.008, which means there is a 0.8% chance of his locker combination being 000.*

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