Joyce combines 9 atoms of hydrogen and 3 atoms of nitrogen to make 3 molecules of ammonia (a) write direct variation equation that relates atoms of hydrogen Hto atoms of nitrogen N (B)how many nitrogen atoms does joyce need to form ammonia molecules using 51 hydrogen atoms (C) graph the direct variation with nitrogen along the x-axis.
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Joyce combines 9 atoms of hydrogen and 3 atoms of nitrogen to make 3 molecules of ammonia.
equation for formation of ammonia is:
a = k*h*n --- (i)
(where a is the molecules of ammonia formed, h and n are the atoms of hydrogen and nitrogen taking part in the reaction, k is a constant of proportionality)
To evaluate k, solve this equation for 9 atoms of hydrogen and 3 atoms of nitrogen to produce 3 molecules of ammonia and get,
So the equation (i) reduces to `a=1/9*h*n` --- (ii)
Again, from equation (ii), it is evident that number of nitrogen atoms reacting=3*number of hydrogen atoms reacting,
i.e. `h=3n` --- (iii)
This is the reqqired direct variation equation to relate atoms of hydrogen to atoms of nitrogen combining with it.
Put h=51 in eq (iii)
The graph of equation (iii) with n in the x-axis and h in the y-axis:
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