# Joyce combines 9 atoms of hydrogen and 3 atoms of nitrogen to make 3 molecules of ammonia (a) write direct variation equation that relates atoms of hydrogen Hto atoms of nitrogen N (B)how many...

Joyce combines 9 atoms of hydrogen and 3 atoms of nitrogen to make 3 molecules of ammonia (a) write direct variation equation that relates atoms of hydrogen Hto atoms of nitrogen N (B)how many nitrogen atoms does joyce need to form ammonia molecules using 51 hydrogen atoms (C) graph the direct variation with nitrogen along the x-axis.

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### 1 Answer

Joyce combines 9 atoms of hydrogen and 3 atoms of nitrogen to make 3 molecules of ammonia.

equation for formation of ammonia is:

a = k*h*n --- (i)

(where a is the molecules of ammonia formed, h and n are the atoms of hydrogen and nitrogen taking part in the reaction, k is a constant of proportionality)

To evaluate k, solve this equation for 9 atoms of hydrogen and 3 atoms of nitrogen to produce 3 molecules of ammonia and get,

3=k*9*3

`rArr k=1/9`

So the equation (i) reduces to `a=1/9*h*n` --- (ii)

Again, from equation (ii), it is evident that number of nitrogen atoms reacting=3*number of hydrogen atoms reacting,

i.e. `h=3n` --- (iii)

This is the reqqired direct variation equation to relate atoms of hydrogen to atoms of nitrogen combining with it.

Put h=51 in eq (iii)

n=51/3=17

The graph of equation (iii) with n in the x-axis and h in the y-axis:

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